(5x+2)^2+15x+6=0(5x+2)2+15x+6=0

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Solution for (5x+2)^2+15x+6=0(5x+2)2+15x+6=0 equation: 



(5x+2)^2+15x+6=0(5x+2)2+15x+6=0

We move all terms to the left:

(5x+2)^2+15x+6-(0(5x+2)2+15x+6)=0

We add all the numbers together, and all the variables

15x+(5x+2)^2-(0(5x+2)2+15x+6)+6=0



We calculate terms in parentheses: -(0(5x+2)2+15x+6), so:

0(5x+2)2+15x+6

We add all the numbers together, and all the variables

15x+0(5x+2)2+6

We multiply parentheses

15x+10x+4+6

We add all the numbers together, and all the variables

25x+10

Back to the equation:

-(25x+10)



We get rid of parentheses

15x+(5x+2)^2-25x-10+6=0

We add all the numbers together, and all the variables

-10x+(5x+2)^2-4=0

We move all terms containing x to the left, all other terms to the right

-10x+(5x+2)^2=4

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